好的处理

1 [email protected] 96
2 [email protected] 88
3 [email protected] 87
3 [email protected] 87
5 [email protected] 80
5 [email protected] 80
输出前5名
for(int i=1,j=i;i<=k;i=j)
{
while(a[i].fen==a[j].fen)
{
cout<<i<<" "<<a[j].id<<" "<<a[j++].fen<<endl;
}
}