实验5

实验5

实验结论:

实验任务1:

源码:

Publisher.hpp

#pragma once

#include <string>

// 发行/出版物类:Publisher (抽象类)
class Publisher
{
public:
    Publisher(const std::string &name_ = ""); // 构造函数
    virtual ~Publisher() = default;

public:
    virtual void publish() const = 0; // 纯虚函数,作为接口继承
    virtual void use() const = 0;     // 纯虚函数,作为接口继承

protected:
    std::string name; // 发行/出版物名称
};

// 图书类: Book
class Book : public Publisher
{
public:
    Book(const std::string &name_ = "", const std::string &author_ = ""); // 构造函数

public:
    void publish() const override; // 接口
    void use() const override;     // 接口

private:
    std::string author; // 作者
};

// 电影类: Film
class Film : public Publisher
{
public:
    Film(const std::string &name_ = "", const std::string &director_ = ""); // 构造函数

public:
    void publish() const override; // 接口
    void use() const override;     // 接口

private:
    std::string director; // 导演
};

// 音乐类:Music
class Music : public Publisher
{
public:
    Music(const std::string &name_ = "", const std::string &artist_ = "");

public:
    void publish() const override; // 接口
    void use() const override;     // 接口

private:
    std::string artist; // 音乐艺术家名称
};

Publisher.cpp

#include <iostream>
#include <string>
#include "publisher.hpp"

// Publisher类:实现
Publisher::Publisher(const std::string &name_) : name{name_}
{
}

// Book类: 实现
Book::Book(const std::string &name_, const std::string &author_) : Publisher{name_}, author{author_}
{
}

void Book::publish() const
{
    std::cout << "Publishing book《" << name << "》 by " << author << '\n';
}

void Book::use() const
{
    std::cout << "Reading book 《" << name << "》 by " << author << '\n';
}

// Film类:实现
Film::Film(const std::string &name_, const std::string &director_) : Publisher{name_}, director{director_}
{
}

void Film::publish() const
{
    std::cout << "Publishing film <" << name << "> directed by " << director << '\n';
}

void Film::use() const
{
    std::cout << "Watching film <" << name << "> directed by " << director << '\n';
}

// Music类:实现
Music::Music(const std::string &name_, const std::string &artist_) : Publisher{name_}, artist{artist_}
{
}

void Music::publish() const
{
    std::cout << "Publishing music <" << name << "> by " << artist << '\n';
}

void Music::use() const
{
    std::cout << "Listening to music <" << name << "> by " << artist << '\n';
}

task1.cpp

#include <memory>
#include <iostream>
#include <vector>
#include "publisher.hpp"

void test1()
{
    std::vector<Publisher *> v;

    v.push_back(new Book("Harry Potter", "J.K. Rowling"));
    v.push_back(new Film("The Godfather", "Francis Ford Coppola"));
    v.push_back(new Music("Blowing in the wind", "Bob Dylan"));

    for (Publisher *ptr : v)
    {
        ptr->publish();
        ptr->use();
        std::cout << '\n';
        delete ptr;
    }
}

void test2()
{
    std::vector<std::unique_ptr<Publisher>> v;

    v.push_back(std::make_unique<Book>("Harry Potter", "J.K. Rowling"));
    v.push_back(std::make_unique<Film>("The Godfather", "Francis Ford Coppola"));
    v.push_back(std::make_unique<Music>("Blowing in the wind", "Bob Dylan"));

    for (const auto &ptr : v)
    {
        ptr->publish();
        ptr->use();
        std::cout << '\n';
    }
}

void test3()
{
    Book book("A Philosophy of Software Design", "John Ousterhout");
    book.publish();
    book.use();
}

int main()
{
    std::cout << "运行时多态:纯虚函数、抽象类\n";

    std::cout << "\n测试1: 使用原始指针\n";
    test1();

    std::cout << "\n测试2: 使用智能指针\n";
    test2();

    std::cout << "\n测试3: 直接使用类\n";
    test3();
}

运行测试截图:

结果

回答问题:

问题1:

(1)是什么决定了 Publisher 是抽象类?用一句话说明,并指出代码中的具体依据。

因为它包含纯虚函数。依据:在 publisher.hpp 里有形如 virtual void publish() const = 0; 的声明。

(2)如果在 main.cpp 里直接写 Publisher p; 能否编译通过?为什么?

不能编译通过。因为抽象类不能实例化(含有纯虚函数)。

问题2:

(1)Book 、 Film 、 Music 必须实现哪两个函数才能通过编译?请写出其完整函数声明。

void publish() const; 和 void info() const;

void publish() const override;
void info() const override;

(2)在 publisher.cpp 的 Film 类实现中,把两个成员函数实现里的 const 去掉(保持函数体不变),重新编译,报错信息是什么?

报错

问题3:

(1)在 test1() 里, for (Publisher *ptr : v) 中 ptr 的声明类型是什么?

Publisher*

(2)当循环执行到 ptr->publish(); 时, ptr 实际指向的对象类型分别有哪些?(按循环顺序写出)

Book、Film、Music。

(3)基类 Publisher 的析构函数为何声明为 virtual ?若删除 virtual ,执行 delete ptr; 会出现什么问题?

基类析构函数声明为 virtual 是为了多态删除,确保 delete ptr; 时能调用派生类析构函数。若无 virtual,delete 只调用基类析构,导致资源泄漏。

实验任务2:

源码:

book.hpp

#pragma once
#include <string>

// 图书描述信息类Book: 声明
class Book
{
public:
    Book(const std::string &name_,
         const std::string &author_,
         const std::string &translator_,
         const std::string &isbn_,
         double price_);

    friend std::ostream &operator<<(std::ostream &out, const Book &book);

private:
    std::string name;       // 书名
    std::string author;     // 作者
    std::string translator; // 译者
    std::string isbn;       // isbn号
    double price;           // 定价
};

book.cpp

#include <iomanip>
#include <iostream>
#include <string>
#include "book.hpp"

// 图书描述信息类Book: 实现
Book::Book(const std::string &name_,
           const std::string &author_,
           const std::string &translator_,
           const std::string &isbn_,
           double price_) : name{name_}, author{author_}, translator{translator_}, isbn{isbn_}, price{price_}
{
}

// 运算符<<重载实现
std::ostream &operator<<(std::ostream &out, const Book &book)
{
    using std::left;
    using std::setw;

    out << left;
    out << setw(15) << "书名:" << book.name << '\n'
        << setw(15) << "作者:" << book.author << '\n'
        << setw(15) << "译者:" << book.translator << '\n'
        << setw(15) << "ISBN:" << book.isbn << '\n'
        << setw(15) << "定价:" << book.price;

    return out;
}

booksale.hpp

#pragma once

#include <string>
#include "book.hpp"

// 图书销售记录类BookSales:声明
class BookSale
{
public:
    BookSale(const Book &rb_, double sales_price_, int sales_amount_);
    int get_amount() const;     // 返回销售数量
    double get_revenue() const; // 返回营收

    friend std::ostream &operator<<(std::ostream &out, const BookSale &item);

private:
    Book rb;
    double sales_price; // 售价
    int sales_amount;   // 销售数量
};

booksale.cpp

#include <iomanip>
#include <iostream>
#include <string>
#include "booksale.hpp"

// 图书销售记录类BookSales:实现
BookSale::BookSale(const Book &rb_,
                   double sales_price_,
                   int sales_amount_) : rb{rb_}, sales_price{sales_price_}, sales_amount{sales_amount_}
{
}

int BookSale::get_amount() const
{
    return sales_amount;
}

double BookSale::get_revenue() const
{
    return sales_amount * sales_price;
}

// 运算符<<重载实现
std::ostream &operator<<(std::ostream &out, const BookSale &item)
{
    using std::left;
    using std::setw;

    out << left;
    out << item.rb << '\n'
        << setw(15) << "售价:" << item.sales_price << '\n'
        << setw(15) << "销售数量:" << item.sales_amount << '\n'
        << setw(15) << "营收:" << item.get_revenue();

    return out;
}

task2.cpp

#include <algorithm>
#include <iomanip>
#include <iostream>
#include <string>
#include <vector>
#include "booksale.hpp"

// 按图书销售数量比较
bool compare_by_amount(const BookSale &x1, const BookSale &x2)
{
    return x1.get_amount() > x2.get_amount();
}

void test()
{
    using std::cin;
    using std::cout;
    using std::getline;
    using std::sort;
    using std::string;
    using std::vector;
    using std::ws;

    vector<BookSale> sales_records; // 图书销售记录表

    int books_number;
    cout << "录入图书数量: ";
    cin >> books_number;

    cout << "录入图书销售记录\n";
    for (int i = 0; i < books_number; ++i)
    {
        string name, author, translator, isbn;
        double price;
        cout << string(20, '-') << "第" << i + 1 << "本图书信息录入" << string(20, '-') << '\n';
        cout << "录入书名: ";
        getline(cin >> ws, name);
        cout << "录入作者: ";
        getline(cin >> ws, author);
        cout << "录入译者: ";
        getline(cin >> ws, translator);
        cout << "录入isbn: ";
        getline(cin >> ws, isbn);
        cout << "录入定价: ";
        cin >> price;

        Book book(name, author, translator, isbn, price);

        double sales_price;
        int sales_amount;

        cout << "录入售价: ";
        cin >> sales_price;
        cout << "录入销售数量: ";
        cin >> sales_amount;

        BookSale record(book, sales_price, sales_amount);
        sales_records.push_back(record);
    }

    // 按销售册数排序
    sort(sales_records.begin(), sales_records.end(), compare_by_amount);

    // 按销售册数降序输出图书销售信息
    cout << string(20, '=') << "图书销售统计" << string(20, '=') << '\n';
    for (auto &record : sales_records)
    {
        cout << record << '\n';
        cout << string(40, '-') << '\n';
    }
}

int main()
{
    test();
}

运行测试截图:

结果

回答问题:

问题1:

(1)找出运算符 << 被重载了几处?分别用于什么类型?

2处,分别用于 Book 和 BookSale 类型。

(2)找出使用重载 << 输出对象的代码,写在下面。

cout << book;
cout << sale;

问题2:

(1)图书销售记录"按销售数量降序排序",代码是如何实现的?

通过自定义比较函数(如 compareBySaleCount),用 sort(v.begin(), v.end(), compareBySaleCount); 实现降序排序。

(2)拓展(选答*):如果使用lambda表达式,如何实现"按销售数量降序排序"?

sort(v.begin(), v.end(), [](const BookSale &a, const BookSale &b) { return a.getCount() > b.getCount(); });

实验任务4:

源码:

Pet.hpp

#ifndef PET_HPP
#define PET_HPP

#include <string>

// 抽象基类:机器宠物
class MachinePet
{
private:
    std::string nickname; // 宠物昵称

public:
    // 初始化昵称
    MachinePet(const std::string &name) : nickname(name) {}

    // 获取昵称
    const std::string &get_nickname() const
    {
        return nickname;
    }

    // 纯虚函数:宠物叫声
    virtual std::string talk() const = 0;

    // 虚析构函数
    virtual ~MachinePet() = default;
};

// 派生类:机器猫
class PetCat : public MachinePet
{
public:
    // 调用父类构造初始化昵称
    PetCat(const std::string &name) : MachinePet(name) {}

    // 实现猫的叫声
    std::string talk() const override
    {
        return "Meow~";
    }
};

// 派生类:机器狗
class PetDog : public MachinePet
{
public:
    // 调用父类构造初始化昵称
    PetDog(const std::string &name) : MachinePet(name) {}

    // 实现狗的叫声
    std::string talk() const override
    {
        return "Woof~";
    }
};

#endif // PET_HPP

task4.cpp

#include <iostream>
#include <memory>
#include <vector>
#include "pet.hpp"

void test1()
{
    std::vector<MachinePet *> pets;

    pets.push_back(new PetCat("miku"));
    pets.push_back(new PetDog("da huang"));

    for (MachinePet *ptr : pets)
    {
        std::cout << ptr->get_nickname() << " says " << ptr->talk() << '\n';
        delete ptr; // 须手动释放资源
    }
}

void test2()
{
    std::vector<std::unique_ptr<MachinePet>> pets;

    pets.push_back(std::make_unique<PetCat>("miku"));
    pets.push_back(std::make_unique<PetDog>("da huang"));

    for (auto const &ptr : pets)
        std::cout << ptr->get_nickname() << " says " << ptr->talk() << '\n';
}

void test3()
{
    // MachinePet pet("little cutie");   // 编译报错:无法定义抽象类对象

    const PetCat cat("miku");
    std::cout << cat.get_nickname() << " says " << cat.talk() << '\n';

    const PetDog dog("da huang");
    std::cout << dog.get_nickname() << " says " << dog.talk() << '\n';
}

int main()
{
    std::cout << "测试1: 使用原始指针\n";
    test1();

    std::cout << "\n测试2: 使用智能指针\n";
    test2();

    std::cout << "\n测试3: 直接使用类\n";
    test3();
}

运行测试截图:

结果

实验任务5:

源码:

Complex.hpp

#ifndef COMPLEX_HPP
#define COMPLEX_HPP

#include <iostream>

// 复数类模板
template <typename T>
class Complex
{
private:
    T real_; // 实部
    T imag_; // 虚部

public:
    Complex() : real_(0), imag_(0) {}
    Complex(T real, T imag) : real_(real), imag_(imag) {}
    Complex(const Complex<T> &other) : real_(other.real_), imag_(other.imag_) {}

    // 获取实部
    T get_real() const
    {
        return real_;
    }

    // 获取虚部
    T get_imag() const
    {
        return imag_;
    }

    // 4. 重载 += 运算符
    Complex<T> &operator+=(const Complex<T> &other)
    {
        this->real_ += other.real_;
        this->imag_ += other.imag_;
        return *this;
    }

    // 5. 重载 == 运算符
    bool operator==(const Complex<T> &other) const
    {
        return (this->real_ == other.real_) && (this->imag_ == other.imag_);
    }

    // 声明友元:重载 << 输出运算符
    template <typename U>
    friend std::ostream &operator<<(std::ostream &os, const Complex<U> &c);

    // 声明友元:重载 >> 输入运算符
    template <typename U>
    friend std::istream &operator>>(std::istream &is, Complex<U> &c);
};

// 6. 重载 + 运算符
template <typename T>
Complex<T> operator+(const Complex<T> &c1, const Complex<T> &c2)
{
    // 复用 += 逻辑,避免代码冗余
    Complex<T> res = c1;
    res += c2;
    return res;
}

// 7. 重载 << 输出运算符
template <typename T>
std::ostream &operator<<(std::ostream &os, const Complex<T> &c)
{
    os << c.real_;
    if (c.imag_ >= 0)
    {
        os << " + " << c.imag_ << "i";
    }
    else
    {
        os << " - " << -c.imag_ << "i";
    }
    return os;
}

// 8. 重载 >> 输入运算符
template <typename T>
std::istream &operator>>(std::istream &is, Complex<T> &c)
{
    is >> c.real_ >> c.imag_;
    return is;
}

#endif // COMPLEX_HPP

task5.cpp

#include <iostream>
#include "Complex.hpp"

void test1()
{
    using std::boolalpha;
    using std::cout;

    Complex<int> c1(2, -5), c2(c1);

    cout << "c1 = " << c1 << '\n';
    cout << "c2 = " << c2 << '\n';
    cout << "c1 + c2 = " << c1 + c2 << '\n';

    c1 += c2;
    cout << "c1 = " << c1 << '\n';
    cout << boolalpha << (c1 == c2) << '\n';
}

void test2()
{
    using std::cin;
    using std::cout;

    Complex<double> c1, c2;
    cout << "Enter c1 and c2: ";
    cin >> c1 >> c2;
    cout << "c1 = " << c1 << '\n';
    cout << "c2 = " << c2 << '\n';

    const Complex<double> c3(c1);
    cout << "c3.real = " << c3.get_real() << '\n';
    cout << "c3.imag = " << c3.get_imag() << '\n';
}

int main()
{
    std::cout << "自定义类模板Complex测试1: \n";
    test1();

    std::cout << "\n自定义类模板Complex测试2: \n";
    test2();
}

运行测试截图:

结果

posted @ 2025-12-15 21:54  .Maring  阅读(3)  评论(0)    收藏  举报