摘要：
l = ['leo','yao','y'] l.append('yao') l.pop() print(1) t = ('leo','yao','y') scores = [99,66,89] d = {'leo':99,'yao':66,'y':89} d['yao'] = 99 d['Rose' 阅读全文
posted @ 2018-06-06 21:24
Doshelly
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